Optimal. Leaf size=169 \[ -\frac{7 b^{3/2} (9 A b-5 a B) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{a}}\right )}{4 a^{11/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}-\frac{7 b (9 A b-5 a B)}{4 a^5 \sqrt{x}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2} \]
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Rubi [A] time = 0.0741477, antiderivative size = 169, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {78, 51, 63, 205} \[ -\frac{7 b^{3/2} (9 A b-5 a B) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{a}}\right )}{4 a^{11/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}-\frac{7 b (9 A b-5 a B)}{4 a^5 \sqrt{x}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2} \]
Antiderivative was successfully verified.
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Rule 78
Rule 51
Rule 63
Rule 205
Rubi steps
\begin{align*} \int \frac{A+B x}{x^{7/2} (a+b x)^3} \, dx &=\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}-\frac{\left (-\frac{9 A b}{2}+\frac{5 a B}{2}\right ) \int \frac{1}{x^{7/2} (a+b x)^2} \, dx}{2 a b}\\ &=\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}+\frac{(7 (9 A b-5 a B)) \int \frac{1}{x^{7/2} (a+b x)} \, dx}{8 a^2 b}\\ &=-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{(7 (9 A b-5 a B)) \int \frac{1}{x^{5/2} (a+b x)} \, dx}{8 a^3}\\ &=-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}+\frac{(7 b (9 A b-5 a B)) \int \frac{1}{x^{3/2} (a+b x)} \, dx}{8 a^4}\\ &=-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac{7 b (9 A b-5 a B)}{4 a^5 \sqrt{x}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{\left (7 b^2 (9 A b-5 a B)\right ) \int \frac{1}{\sqrt{x} (a+b x)} \, dx}{8 a^5}\\ &=-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac{7 b (9 A b-5 a B)}{4 a^5 \sqrt{x}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{\left (7 b^2 (9 A b-5 a B)\right ) \operatorname{Subst}\left (\int \frac{1}{a+b x^2} \, dx,x,\sqrt{x}\right )}{4 a^5}\\ &=-\frac{7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac{7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac{7 b (9 A b-5 a B)}{4 a^5 \sqrt{x}}+\frac{A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac{9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac{7 b^{3/2} (9 A b-5 a B) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{x}}{\sqrt{a}}\right )}{4 a^{11/2}}\\ \end{align*}
Mathematica [C] time = 0.0255903, size = 61, normalized size = 0.36 \[ \frac{\frac{5 a^2 (A b-a B)}{(a+b x)^2}+(5 a B-9 A b) \, _2F_1\left (-\frac{5}{2},2;-\frac{3}{2};-\frac{b x}{a}\right )}{10 a^3 b x^{5/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.016, size = 178, normalized size = 1.1 \begin{align*} -{\frac{2\,A}{5\,{a}^{3}}{x}^{-{\frac{5}{2}}}}+2\,{\frac{Ab}{{a}^{4}{x}^{3/2}}}-{\frac{2\,B}{3\,{a}^{3}}{x}^{-{\frac{3}{2}}}}-12\,{\frac{A{b}^{2}}{{a}^{5}\sqrt{x}}}+6\,{\frac{Bb}{{a}^{4}\sqrt{x}}}-{\frac{15\,{b}^{4}A}{4\,{a}^{5} \left ( bx+a \right ) ^{2}}{x}^{{\frac{3}{2}}}}+{\frac{11\,{b}^{3}B}{4\,{a}^{4} \left ( bx+a \right ) ^{2}}{x}^{{\frac{3}{2}}}}-{\frac{17\,{b}^{3}A}{4\,{a}^{4} \left ( bx+a \right ) ^{2}}\sqrt{x}}+{\frac{13\,{b}^{2}B}{4\,{a}^{3} \left ( bx+a \right ) ^{2}}\sqrt{x}}-{\frac{63\,{b}^{3}A}{4\,{a}^{5}}\arctan \left ({b\sqrt{x}{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{35\,{b}^{2}B}{4\,{a}^{4}}\arctan \left ({b\sqrt{x}{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.77826, size = 950, normalized size = 5.62 \begin{align*} \left [-\frac{105 \,{\left ({\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{5} + 2 \,{\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{4} +{\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{3}\right )} \sqrt{-\frac{b}{a}} \log \left (\frac{b x - 2 \, a \sqrt{x} \sqrt{-\frac{b}{a}} - a}{b x + a}\right ) + 2 \,{\left (24 \, A a^{4} - 105 \,{\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{4} - 175 \,{\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{3} - 56 \,{\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2} + 8 \,{\left (5 \, B a^{4} - 9 \, A a^{3} b\right )} x\right )} \sqrt{x}}{120 \,{\left (a^{5} b^{2} x^{5} + 2 \, a^{6} b x^{4} + a^{7} x^{3}\right )}}, -\frac{105 \,{\left ({\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{5} + 2 \,{\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{4} +{\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{3}\right )} \sqrt{\frac{b}{a}} \arctan \left (\frac{a \sqrt{\frac{b}{a}}}{b \sqrt{x}}\right ) +{\left (24 \, A a^{4} - 105 \,{\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{4} - 175 \,{\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{3} - 56 \,{\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2} + 8 \,{\left (5 \, B a^{4} - 9 \, A a^{3} b\right )} x\right )} \sqrt{x}}{60 \,{\left (a^{5} b^{2} x^{5} + 2 \, a^{6} b x^{4} + a^{7} x^{3}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.18908, size = 182, normalized size = 1.08 \begin{align*} \frac{7 \,{\left (5 \, B a b^{2} - 9 \, A b^{3}\right )} \arctan \left (\frac{b \sqrt{x}}{\sqrt{a b}}\right )}{4 \, \sqrt{a b} a^{5}} + \frac{11 \, B a b^{3} x^{\frac{3}{2}} - 15 \, A b^{4} x^{\frac{3}{2}} + 13 \, B a^{2} b^{2} \sqrt{x} - 17 \, A a b^{3} \sqrt{x}}{4 \,{\left (b x + a\right )}^{2} a^{5}} + \frac{2 \,{\left (45 \, B a b x^{2} - 90 \, A b^{2} x^{2} - 5 \, B a^{2} x + 15 \, A a b x - 3 \, A a^{2}\right )}}{15 \, a^{5} x^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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